A path 5m wide runs along inside a rectangular field. The length of the rectangular field is three times the breadth of the field. if the area of the path is 500m2, then find the length and breadth of the field..

Length = 45m

Breadth = 15m

Step-by-step explanation:

Dimensions of Rectangular field:

Let the breadth (B)=BC = x m

Length (L) = AB = 3x m

width of the road (w) = 5 m

Dimensions of inner rectangle:

length (l) = EF = L-2w

= 3x - 2×5

= (3x-10) m

breadth (b)=EH = B-2w

= (x-10) m

Given ,

Area of the path =500 m²

=> Area of ABCD - Area of EFGH = 500

=> L×B - l×b=500

=> (3x)× x - (3x-10)(x-10)=500

=> 3x²-(3x²-30x-10x+100)=500

=> 3x²-3x²+30x+10x-100=500

=> 40x=500+100

=> 40x = 600

=> x = 600/40

=> x = 15

Therefore,

Length (L) = 3x = 3×15 = 45m

Breadth (B) = x = 15m

Mark me as brainliest if it was helpful

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.