PLS HELP I REALLY NEED HELP THIS IS MY LAST QUESTION I WILL GIVE BRAINLIEST THE PERSON WHO HAS THE CORRECT ANSWER PLS DON"T PUT STUPID ANSWERS find an equation of the line that has a y intercept of 5 and is perpendicular to the graph of the line 4x+3y=8.

y = 3/4x + 5

-3x + 4y = 20

Step-by-step explanation:

In order to write this equation, you need the slope and y-intercept (I'll answer in slope-intercept form and standard form)

First change that standard form equation to slope-intercept form:

1. 4x + 3y = 8

2. 3y = -4x + 8

3. y = -4/3x + 8/3

Step 1 is given.

In step 2, 4x was subtracted from both sides.

In step 3, both sides were divided by 3.

Slope-intercept form:

y = mx + b

m is the slope and b is the y-intercept.

m = 3/4; the slope of a line perpendicular to another line is the negative reciprocal of the other line's slope (ex: line's slope is 1/4; a line perpendicular to it has a slope of -4, the negative reciprocal)

b = 5; the y-intercept was stated in the problem

Now, you put it together: y = 3/4x + 5

Standard form:

You can just change the slope intercept form back into standard form by moving the numbers around a bit:

1. y = 3/4x + 5

2. -3/4x + y = 5

3. -3x + 4y = 20

Step 1 is given.

In step 2, 3/4x was subtracted from both sides of the equation.

In step 3, both sides were multiplied by 4 so that the equation could have nice whole numbers. (this step is optional, I just think it's easier to read this way)

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step-by-step explanation:

hopefully im right

answer: (1,3) and (-2,0) i think.