A mother is 33 years older than her twin children. In 3 years her age will be twice the combined ages of the twins. How old are the twins now?

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  30

Step-by-step explanation:

Let m represent the mother's age in 3 years. At that point in time, her age is twice a twin's age, which is m-33:

  m = 2(m -33)

  m = 2m -66 . . . . eliminate parentheses

  66 = m . . . . . . . . add 66-m

In 3 years, the mother's age will be 66. Each twin is now 36 years younger.

The twins are 30 years old now.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the answer will be b x² +x-1

step-by-step explanation: