The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than the width . Find the dimensions.

width: 33 ft

length: 74 ft

Step-by-step explanation:

The perimeter of a rectangle is calculated by adding all of the sides together which includes two lengths and two widths. Since the formula for the length is given (l = 41ft + w) and the perimeter is given, then we can simply use the perimeter formula and substitute the value of length with its formula which would only leave us with one variable in the equation w. Now we must solve for w.

l + l + w + w = 214

(41 + w) + (41 +w) + w + w = 214  ... combine like terms

82 + 4w = 214  ... subtract 82 from both sides

4w = 132 ... divide both sides by 4

w = 33 ft

Finally, we can see that the value of the width is 33 ft . Now we plug this value into the formula for length to calculate its value.

l = 41 + w

l = 41 + 33

l = 74 ft

answer:   rlly

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.