Please help!! Square ABCD has vertices A(-2,-3), B(4, -1), C(2,5), and D(-4,3). Find the length of a side

of the square. Round your answer to the nearest tenth if necessary.

The length of a side of the square is 6.3 units.

Step-by-step explanation:

When given vertices for a given shape, the length of the side is calculated using the formula:

√(x2 - x1)² + (y2 - y1)²

When given vertices (x1 , y1) and (x2 , y2)

Square ABCD has vertices A(-2,-3), B(4, -1), C(2,5), and D(-4,3). Find the length of a side

Side AB : A(-2,-3), B(4, -1)

√(x2 - x1)² + (y2 - y1)²

= √(4 -(-2))² + (-1 -(-3))²

= √ 6² + 2²

= √36 + 4

= √40

= 6.3245553203

≈ 6.3 units

B(4, -1), C(2,5),

√(x2 - x1)² + (y2 - y1)²

= √ (2- 4)² + (5- (-1))²

= √-2² + 6²

= √4 + 36

= √40

= 6.3245553203

≈ 6.3 units

C(2,5), D(-4,3).

√(x2 - x1)² + (y2 - y1)²

= √(-4 - 2)² + (3 - 5)²

= √-6² + -2²

= √36 + 4

= √40

= 6.3245553203

≈ 6.3 units

A(-2,-3), D(-4,3).

√(x2 - x1)² + (y2 - y1)²

= √(-4 -(-2))² + (3 - (-3))²

= √-2² + 6²

= √4 + 36

= √40

= 6.3245553203

≈ 6.3 units

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

kekdkdkccc

so

step-by-step explanation:

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