Question 1: On a coordinate plane, triangle ABC has vertices at A(10,5), B(10,15), and C(5,5). Triangle A'B'C' has vertices at A' (30,12), B'(30,52), and C(10,12). Which transformation maps triangle ABC onto triangle A'B'C'? A. (x, y) --> (3x, 3y + 3) B. (x, y) --> (4x - 10, 4y - 8) C. (x, y) --> (4x + 10, 4y + 8) D. (x, y) -> (3x, 3y - 3)

B. (x,y) --> (4x - 10, 4y - 8)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.

If a point X(x, y) is translated a units right and b units up, the new location is (x + a, y + b) also If a point X(x, y) is translated a units left and b units down, the new location is (x - a, y - b)

If a point X(x, y) is dilated by the factor k the new location is X'(kx, ky).

Triangle ABC has vertices at A(10,5), B(10,15), and C(5,5), If it is dilated by a factor of 4, the new location is A*(40, 20), B*(40, 60) and C*(20, 20). If then a translation of 10 units left and 8 units down, the new points are A'(30, 12), B'(30, 52), C'(10, 12).

This is a transformation of (x,y) --> (4x - 10, 4y - 8)

darn right!

step-by-step explanation:

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i dont understand the question? ?

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