|x| - 8 = -4
How do i solve this...
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What constants do you need to add to each of the following quadratic equations to complete the square? 2x2 - 3x = 0 x2 - 8x = 0 2x2 - 11x = 18
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If sec theta = 5/3 and the terminal point determined by theta is in quadrant 4, then
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