Enter decimal numbers in the boxes to identify the point in Quadrant III which is 3 units away from point A.

(-0.5, -0.5)

Step-by-step explanation:

Let the coordinates of the point P in quadrant 3 are (x, y).

If a point A is 3 units apart, coordinates of point P will be [(x - 3), y].

From the figure attached,

Coordinates of the point A are (2.5, -0.5).

x coordinate of point P → (2.5 - 3) = -0.5

y coordinate of the point P → (-0.5) = -0.5

Therefore, point P which is 3 units apart from A will be (-0.5, -0.5)

eve and marks ratios are equivalent

step-by-step explanation:

answer: r there any options?

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