Factor 9r2 – 36r – 45.

9(r - 5)(r - 1)

Step-by-step explanation:

9r^2 - 36r - 45

First, factor out 9

9(r^2 - 4r - 5)

Then you can factor what's inside the parentheses

9(r - 5)(r -1 )

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

the answer is c just got it on ed

step-by-step explanation: