Find the height of a triangle that has an area of 18 in.² and a base of 9in. PLZ SHOW STEP AND STEP CUZ I NEED TO SHOW MY WORK

The height of the triangle is 4 in.

Step-by-step explanation:

Formula= a=1/2bh

Subsitute= 18 in^2=1/2(9)h

Multiply= (9)1/2= 4.5 in.

Divide 18/4.5= 4 in.

So the height would be 4 in.

Check If you aren't sure.

a=1/2bh

a=1/2(9)(4)

a=1/2(36)

a=18 in^2

The height of the triangle is 4 in.

Step-by-step explanation:

Formula= a=1/2bh

Subsitute= 18 in^2=1/2(9)h

Multiply= (9)1/2= 4.5 in.

Divide 18/4.5= 4 in.

So the height would be 4 in.

Check If you aren't sure.

a=1/2bh

a=1/2(9)(4)

a=1/2(36)

a=18 in^2

for this case we have the following expression:

to solve, we rewrite the expression as:

we apply double c and we have:

thus, the quotient is 48.

so, patel found a wrong ratio and the multiplication was incorrect.

option d

the correct answer to your question is a. 4^4

good luck my friend!

hope this !

maybe if i you could me by giving me brainliest?

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