A plumber charges $75 for a service call, plus a $40 per hour. If the plumber's bill was $235, then how many hours was he there?

4 hours

Step-by-step explanation:

235-75 one time fee, so subtract = 160

160/40 = 4

4 Hours

40x - 75 = 235

         -75    -75

40x  = 160

40x/40 = 160/40

x = 4

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.