Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negative slope goes through points (negative 20, 10), (0, 0), and (20, negative 10). (10, –20) (–30, 20) (–10, 5) (35, –20)

(5, 20)  

Step-by-step explanation:

We can find the slope of the line

m = (y2-y1)/(x2-x1)

   = (40-0)/(10-0)

   = 40/10

   =4

Since the line goes through (0,0) the y intercept is 0

y = mx+b

y = 4x

Lets check the points  by substituting into the equation

40, 10)     10 = 4*40   10 =160  no

(–5, –10)    -10 = 4*-5    10 = -20   no

(5, 20)       20 = 4*5    20 = 20  yes

(–10, –20)    -20 = 4*-10    -20 = -40   no

Step-by-step explanation:

Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negative slope goes through points (negative 20, 10), (0, 0), and (20, negative 10). (10, –20) (–30, 20) (–10, 5) (35, –20)

answer:  

123455421

step-by-step explanation: easy

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3