Write the equation of a line that is perpendicular to y= 3x-2 and that passes through the point (-9,5)

Ans: y = (-1/3)x + 2

Step-by-step explanation:

Perpendicular lines have slopes whose product is -1.  The slope given in

y = 3x - 2

is -3.

The slope of the perpendicular line will be m, and m needs to satisfy the equation

3 * m = -1

Hence m = -1/3.

Our perpendicular line is thus

y = (-1/3)x + b

for some constant b.

We are told that the perpendicular line goes through the point (-9,5).  If so, then the following must hold:

5 = (-1/3)(-9) + b

= 3 + b

b = 2

Ans: y = (-1/3)x + 2

(-5,-28)

i graphed to on desmos.