X^2-10x+27 in the form (x-a)^2+B

(x-5)^2+2

Step-by-step explanation:

To convert between standard and vertex form, you have to complete the square (which, as a reminder, (a+b)^2 = a^2+2ab+b^2).

Since a^2 is x^2, and 2ab is -10x, then b must be -5, so b^2 is 25. Therefore, we add and subtract 25 from the expression:

(x-10x+25)+27-25

Then, we can make (x-10x+25) to (x-5)^2:

(x-5)^2+2

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

it is 570

step-by-step explanation: