1.6.PS-21 Question Help Challenge A gold mine has two elevators, one for equipment and another for the miners. The equipment elevator descends 5 feet per second. The elevator for the miners descends 17 feet per second. One day, the equipment elevator begins to descend. After 29 seconds, the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 16 seconds? At that time, which elevator is deeper? The position of the equipment elevator relative to the surface is feet

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Step-by-step explanation:

Given the following :

Equipment elevator :

Descent rate = 5 ft/s

Miner's elevator :

Descent rate = 17 ft/s

Position of elevator after 16 seconds

Total descent time of equipment elevator = (29 + 16) = 45 seconds

Position after 45 Seconds :

Descent rate * time

5ft/s * 45s = 225 ft

Descent time of Miner's elevator = 16 seconds

Position after 16 Seconds :

Descent rate * time

17ft/s * 16s = 272 fts

Miner's elevator is deeper = 272 feets > 225 fts

Position of equipment elevator relative to the surface = - 225fts

answer is because 4×10=40

and 98×4= is 392

40,392

i believe it is b and c. (side note, i got the same computer from k-12 lol i’m in 8th grade and this is my first year, will it get

step-by-step explanation: