What is the equation of the line that passes through the point (-3, 5) with a slope of 4? y=4-7
O y-4x+17
O y= 4x+12
O y=47-17
o y = 4x+2

y=4x+17

Step-by-step explanation:

y-b=m(x-a)

y-5=4(x--3)

y-5=4(x+3)

y-5=4x+12

y=4x+17

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204