2. Tina uSUally brings her children every Sunday afternoon at the children's park in their barangay. The park is 350m Iong and 200m wide complete with slides and swings for children to play. If is surounded by a pathway of unifom width for children who loves biking and jogging. Suppose the total area of the park and the pathway is 74,464 m2.

a. How wide is the pathway of the park?
b. If you were Tina, woulad you like your children fo go biking and jogging in that park?

kindly check explanation

Step-by-step explanation:

Given the following :

Total area of parknand path way = 74,464 m2.

Dimension of park = 350m by 200m

Using the area of rectangle formula:

Area = Length * width

Area of park = 350m * 200m

Area of park = 70,000

Area of path = (74,464 - 70,000) = 4,464m2

Since path has uniform width, then width of the the path is sqrt(4464) = 66.8m

2.) the path of the park seems a bit narrow, hence, I wouldn't love children to bike and jog in such a narrow path

can you post the graph?

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.