Given n > 3, find the probability, Rn, that a random permutation of [n] has no cycle of length > n/3. Expressed you answer as a sum that DOES NOT involve binomial coefficients or factorials.

a is the correct

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

homozygous. one is homozygous, while two is heterozygous.

answer: this is not a question

step-by-step explanation: this is a answer