Draw the image of ABC under dilation whose center is P and scale factor is 4.

By plotting points A', B' and C' we can get the dilated image A'B'C'.

Step-by-step explanation:

Let the point P is origin (0, 0), segment AB lies on the x-axis and segment PC on the y-axis,

Coordinates of A, B and C will be (1, 0), (2, 0) and (0, 2).

When triangle ABC is dilated by a scale factor 4 about the origin,

Rule for dilation;

(x, y) → (4x, 4y)

New coordinates of the points A, B and C will be,

A(1, 0) → A'(4, 0)

B(-2, 0) → B'(-8, 0)

C(0, 2) → C'(0, 8)

the answer is d

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.