Find the standard form of an ellipse where all of its points are in Quadrant IV except (0,-6) and (10,0). (The ellipse is tangent to these 2 points).

answer is b

step-by-step explanation:

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076

2+2 obliviously is 4.