All ball is thrown into the air with an upward velocity of 24 ft/s. its height h in feet after t seconds is given by the function h=-16t^2+24t+7. a. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. b. what is the ball's maximum height?

t=¬b2a; this would be a much easier method. a=¬16 and b=24. We simply plug these values into, followed by simplifying the t value for the time, and then insert this value into h(t) for the height at t. This is one of the ways of determining the maximum of a quadratic function. 

42

step-by-step explanation:

256/6=42

you can't solve x because it is 2 linear equation and you only have one equation