Jill counted 20 pigs and chickens in the farm. Jack counted a total of 54 legs for the animals. How many chickens were there in the farm?

Let the number of chickens in the farm = x

Let the number of pigs in the farm = y

Number of legs of chickens = 2*x (since chickens have 2 legs)

Number of legs of pigs = 4*y (since pigs have 4 legs)

We are given that there are a total of 20 animals (pigs + chickens)

so, number of chickens + number of pigs = 20

x + y = 20

We are given that there is a total of 54 legs in the farm

so, legs of chickens + legs of pigs = 54

2x + 4y = 54

Solving for number of chickens and pigs:

from the question, we have deduced that:

x + y = 20

2x + 4y = 54

taking the value of x from the first equation and using it in the second equation

x = 20 - y

2(20-y) + 4y = 54

40 - 2y + 4y = 54

40 + 2y = 54

2y = 14

y = 7

Using this value of y in the first equation:

x + y  = 20

x + (7) = 20

x = 13

Therefore, there are 13 chickens and 7 pigs in the farm

the answer i think is a)

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)