Which function's graph has a period of 2?
a. y=cos(x-pi/2)
b. y=3cos pi x
c. y=2 sin 3x
d. y=-4 sin 2x

B is correct.

Function y=3cos(πx) would be period 2.

Step-by-step explanation:

We are given a trigonometric equation. We need to find the function whose period is 2.

Where,

a is amplitude of function.

b is wavelength of function.

c is phase shift of function.

As we know the period of y=cos x is 2π

So, Period of function, y=cos(ax) would be

If we divide 2π by coefficient of x we get period of function.

We are given period is 2

Thus, B is correct. Function y=3cos(πx) would be period 2.

the balance is found at the link

step-by-step explanation: