In 2016, Southwest Airlines boasted that 70% of its flights were on time. If we select 8 Southwest flights at random and assume independence, what is the probability that at least 3 flights are on time

0.9887

Step-by-step explanation:

Let p be the probability that flights are on time.

As per given, p =70% = 0.7

Sample size : n = 8

Let x be a binomial variable that represents the number of fights are on time ( i.e. success).

Using binomial formula:

Now,  the probability that at least 3 flights are on time =

The probability that at least 3 flights are on time = 0.9887

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.