What must be the value of x so that lines a and b are parallel lines cut by transversal f? 10
20
22
32

22

Step-by-step explanation:

96° = (6x - 36)° (alternate exterior angles theorem)

Solve for x using the equation.

96 = 6x - 36

Add 36 to each side

96 + 36 = 6x - 36 + 36

132 = 6x

Divide both sides by 6

132/6 = 6x/6

22 = x

x = 22

three-fourths of an hour

36÷48=0.75

0.75=

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2