Koto’s average velocity along her route was 4.5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west. What was the time of her trip? (There are 60 seconds in 1 minute.) 18.5 minutes 20.4 minutes 2 hours 3 hours

18.5 minutes

Step-by-step explanation:

Koto’s average velocity along her route was 4.5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

5000 meters west - 5000 meters east = 0

20,000 south - 15000 north = 5000 meters

4.5 meters = 1 second

5000 meters = x seconds

Cross Multiply

4.5 × x = 5000 × 1

x = 5000/4.5

x = 1111.11111111 seconds

There are 60 seconds in 1 minute.

60 seconds = 1 minute

1111.11111111 = y minutes

60 × y = 1111.11111111 × 1

y = 1111.11111111/60

y = 18.5185185185 minutes

Approximately = 18.5 minutes

The time of her trip is 18.5 minutes

i think its a.

hope this

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.