Wayne is hanging a string of lights 45 feet long around the 3 sides of his rectangular patio, which is adjacent to his house. The length of his patio, the side along the house, is 5 feet longer than 2 times its width. Find the length and width of the patio.

45=2w+L and L=2w+5          

45=2w+L                                  45=2w+(2w+5)

                                                45=4w+5

                                                40=4w

                                                10=w                  

L=2w+5                                    L=2(10)+5

                                                L=20+5

                                                L=25                        

The length of the patio is 25 feet and the width of one side of the patio is 10 feet. Because there are two width sides and one length side, this all adds up to be 45 feet long.

Can I get brainliest please?

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet