TT Consider 3 trials, each having the same probability of success. Let X denote the

total number of successes in these trials. If E(X) = 1.8, the smallest possible value of Pr{X = 3}?

Construct a probability scenario that results in Pr{X = 3} having the stated value.

(Hint: For part (b), you might start by letting U be a uniform random variable on (0,1) and then defining the trials in terms of the value of U.)

Solve using hint

The smallest possible value of Pr{X = 3} is  U = 0

Step-by-step explanation:

  The number of trial is  n = 3

  The mean is  E(X) = 1.8

Gnerally given that every probability value lies between 0  and 1 ,

let U be the smallest possible value of  Pr{X = 3}

it then mean that U= 0 because in the range which probability values can take , the smallest value is  zero

So

     The smallest possible value of Pr{X = 3} is  U = 0

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6