Let V be the volume of the pyramid of height 11 whose base is a square of side length 6. Find a formula for the area A of the horizontal cross section at a height y.

Base area = 36

Volume of the pyramid = 132

Step-by-step explanation:

Volume of a pyramid = Base Area × Height/3

Base area = Length × Length (since base of the pyramid is a square)

Given the side length of the square = 6

Base area = 6×6

Base area = 36

Given height of pyramid =11

Volume of the pyramid = 36×11/3

Volume of the pyramid = 12×11

Volume of the pyramid = 132

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

answer: it is d

step-by-step explanation: