If 2(x+3)^2=98 find x in this equation.

x = - 10, x = 4

Step-by-step explanation:

Given

2(x + 3)² = 98 ( divide both sides by 2 )

(x + 3)² = 49 ( take the square root of both sides )

x + 3 = ± = ± 7 ( subtract 3 from both sides )

x = - 3 ± 7

Thus

x = - 3 - 7 = - 10

x = - 3 + 7 = 4

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16