after how many seconds is needed for a thrown ball to reach a 14-m distance if it's distance is given by the relation d=10+40t-5t? (t=time in seconds)

The thrown ball will reach a 14-m distance after 0.114 seconds.

The relation given is:

d = 10+40t-5t

where, d = 14

In this case, we've to put the value of d into the relation and this will be:

d = 10+40t-5t

14 = 10 + 40t - 5t

Collect like terms

40t - 5t = 14 - 10

35t = 4

Divide both side by 35

35t/35 = 4/35

t = 0.114 seconds.

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Time, t = 0.1143 seconds.

Step-by-step explanation:

Given that distance, d = 14m

From the equation;

d = 10 + 40t - 5t

d = 10 + 35t

Substituting the value of distance;

14 = 10 + 35t

35t = 14 - 10

35t = 4

t = 4/35

t = 0.1143 seconds.

The time needed for the ball to reach the 14-m distance is 0.1143 seconds.

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source: