Jill says that 23/1000 can be written as 0.23. Which explains whether or not Jill is correct? A. Yes, Jill is correct. The fraction 23/1,000 is equivalent to 0.23. B. No, Jill is not correct. The fraction is equivalent to 0.023. The decimal 0.23 is equivalent to. C. No. Jill is not correct. The fraction is equivalent to 0.0023. The decimal is 0.23 is equivalent to 23/100. D. No, Jill is not correct. The fraction 23/1,000 is equivalent to 2.3. The decimal 0.23 is equivalent to 23/100. D. No, Jill is not correct. The fraction 23/1,000 is equivalent to 2.3. The decimal 0.23 is equivalent to 23/100.

B. No, Jill is not correct, the fraction is equivalent to 0.023.

Step-by-step explanation:

The given fraction is

Observe that in the denominator there is 1000, which has three zeros after 1.

In changing the given fraction to decimal, there must be 3 significant digits after the decimal.

According to this option (b) is correct.

Moreover, when 23 is divided by 1000, we have

But Jill says that 23/1000 can be written as 0.23, so, Jill is not correct.

Hence option (b) is correct,

right

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!