If product of two numbers=384HCF=8,2cm=?

96 and 288

Step-by-step explanation:

So, we need to find 2 numbers such that their sum is 8 and they do not have common factor (Relatively prime). Both these numbers will be divisible by 48 but there would be no other common divisor (after dividing by 48).

Such order independent pairs are (1,7) and (3,5).

Difference between them would be (7–1)*48=6*48 and (5–3)*48=2*48 respectively.

The differences are 6*48=288 and 2*48=96.

We have found difference without finding numbers.

Ans.: 96 and 288

p.s.: The number pairs (again order neutral) would be (48, 336) and (144, 240)

Difference for 48 and 336 add up to 384, their HCF is 48. These two numbers match the conditions. Their difference is 288.

Difference of 144 and 240 add up to 384, their HFC is 48 (the numbers are 48*3 and 48*5, common factor is 48 and no other common factor for 3 and 5; 48 is HCF). The difference is 96.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

no solution

step-by-step explanation:

there is not enough information in the problem to solve.