In one football game, a team scored 24 points with a combination of six-point touchdowns, three-point field goals, and one-point "extra points." They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals. Let x be the number of touchdowns, y be the number of field goals, and z be the number of "extra points." Write a system of equations that can be solved to find how many touchdowns, field goals, and "extra points" the team made. Do not solve your system.

Given:

Total score = 24 points

They made 2 more touchdowns than field goals, and 3 times as many "extra points" as field goals.

To find:

The system of equations for the given problem.

Solution:

Let x be the number of touchdowns.

y be the number of field goals.

z be the number of "extra points."

Total score is 24 points. So,

They made 2 more touchdowns than field goals.

They made 3 times as many "extra points" as field goals.

Therefore, the required system of equation is

765238725478629038640962136509762139056074

step-by-step explanation:

64087235609746097215074621039754021037

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right