What is −58+34 any one know?

-58 + 34 = -24

Step-by-step explanation:

You know what a number line looks like right? Well, you also know that the negative numbers are to the left of the middle of the line at point 0, and the positives are to the right of 0? So, -58 + 34, you would start at -58 and start counting (adding) 34. You do this by "subtracting" a positive 34 from the negative 58, so basically, you could just ignore the negative sign for now and just subtract the problem like this: 58 - 34 = 24. Since 34 is not greater than 58 and you have not "crossed" the middle (0) to get over to the positive side, the answer is still a negative number as your final answer. So, the answer is -58 + 34 = -24.

REMEMBER: On a number line, when you have a negative number and you have to add, you move to the right, or up (if you are doing a vertical line). When you are subtracting on a number line, you move left, or down (if you are doing a vertical line). P.S. I am using the number line example because this is how I add and/or subtract positives and negatives when I don't have a calculator at hand to give the me the answer.

Hope that was helpful and not confusing!!!

the answer is a

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.