a conference hall has 33 rows. the last row contains 80 seats each row has two fewer seats than the row behind it. how many seats are there second to the last row?

there are 84 seats in the  second to the last row

Step-by-step explanation:

Given that

each row has two fewer seats than the row behind it

It means that

if first row has x seats then

no of seat in second row has (x-2) seats.

and similarly

no of seat in third  row =no of seat in second row - 2seats.

no of seat in third  row = (x-2) seat - 2 seats = x - 4 seats

Given that

last row has 80 seats

let the number of seat in first to the last row be x

then number of seat in last row = x-2

we know number of seat in last row = 80

thus

x - 2 = 80

x = 82

Thus,

the number of seat in first to the last row is 82

Similarly let the number of seat in second to the last row be y

then number of seat in first to the  last row = y-2

since number of seat in first to the last row is 82

thus

y-2 = 82

y = 82 + 2 = 84

Thus, there are 84 seats in the  second to the last row.

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841