Mathematics, 18.10.2020 16:01 valeriekbueno

Determine the mean, median, mode, and midrange for this collection of class test scores: 88 82 97 76 79 92 65 84 79 90 75 82 78 77 93 88 95 73 69 89 93 78 60 95 88 72 80 94 88 74 a. Mean is 84, median is 82, mode is 82, midrange is 77 b. Mean is 82, median is 88, mode is 88, midrange is 77 c. Mean is 82.4, median is 88, mode is 82, midrange is 78.5 d. Mean is 82.4, median is 82, mode is 88, midrange is 78.5

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Answer from: GemJock

Mean of a given set of data = Sum of all observations ÷ Total number of observations

Mean of this data set = 88 + 82 + 97 + 76 + 79 + 92 + 65 + 84 + 79 + 90 + 75 + 82 + 78 + 77 + 93 + 88 + 95 + 73 + 69 89 + 93 + 78 + 60 + 95 + 88 + 72 + 80 + 94 + 88 + 74

Mean = 2729 ÷ 30

Mean = 82.4

Median = the middle observation in a given set of data

Median of these test scores = 60 , 65 , 69 , 72 , 73 , 74 , 75 , 76 , 77 , 78 , 78 , 79 , 79 , 80 , 82 , 82 , 84 , 88 , 88 , 88 , 88 , 89 , 90 , 92 , 93 , 93 , 94 , 95 , 95 , 97 .

Median = 82 + 82 / 2

= 164 ÷ 2

= 82

Median = 82

Mode = most frequently occurring number in a given set of data .

Mode of these test scores =

= 60 = 1 time

= 65 = 1 time

= 69 = 1 time

= 72 = 1 time

= 73 = 1 time

= 74 = 1 time

= 75 = 1 time

= 76 = 1 time

= 77 = 1 time

= 78 = 2 times

= 79 = 2 times

= 80 = 1 time

= 82 = 2 times

= 84 = 1 time

= 88 = 4 times

= 89 = 1 time

= 90 = 1 time

= 92 = 1 time

= 93 = 2 times

= 94 = 1 time

= 95 = 2 times

= 97 = 1 time

Mode = 88

Midrange = average of the largest and smallest number in a given set of data

Midrange of these test scores = 97 + 60 / 2

= 97 + 60 / 2

= 157 ÷ 2

= 78.5

Midrange = 78.5

Therefore , the correct option is :-

(d) Mean is 82.4 , median is 82 , mode is 88 , midrange is 78.5

Answer from: Quest

21, i'm pretty sure it's right lol

Answer from: Quest

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where, $a = \frac{\sum y \sum x^2 - \sum x\sum xy}{n\sum x^2 - (\sum x)^2}$

here given table is,

price ($), x : 18 23 25 29 30 33

pairs sold, y : 16 13 10 8 6 2

so, $\sum x = 158$ , $\sum y = 55$ , $\sum xy = 1315$ ,

$\sum x^2 = 4308$ and $\sum y^2 = 629$ ,

thus, slop of the given line is,

$a = \frac{55\times 4308-158\times 1315}{6\times 4308-(158)^2}$

⇒ $a = \frac{29170}{884}$

⇒ $a =32.9977375566$ ≈ 33

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Determine the mean, median, mode, and midrange for this collection of class test scores: 88 82 97 76...

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