Given the quadratic function f(x) = (x + 6)(x – 3): The x-intercepts are
The y-intercept is

Step-by-step explanation:

Given quadratic function is,

f(x) = (x + 6)(x - 3)

For x-intercept,

Substitute the value f(x) = 0.

(x + 6)(x - 3 = 0

x = 3, -6

So the x-intercepts will be,

(-6, 0) and (3, 0)

For y-intercept,

Substitute the value for x = 0,

f(0) = (0 + 6)(0 - 3)

     = -18

Therefore, y-intercept of the given quadratic function will be (0, -18).

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.