An object’s volume is 0.12 kL. What is its volume in liters?

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Idon’t understand! use slope intercept form to solve: through: (2,5) slope= undefined

At $1.32 million, they closed last month percent above what they paid in 2007." how much did they pay in 2007?