If a, b,c, d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)( x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

36

Step-by-step explanation:

Hello,

If it becomes

and

So,

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

44

step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb