Refer to the rectangle shown. Suppose the width of 4 inches is decreased by 3 inches. a. Find the percent of change in the perimeter.
b. Find the percent of change in the area.

a.  30% decrease in perimeter

b.  75% decrease in area

Step-by-step explanation:

Before decrease:

  Perimeter = 2L + 2W = 2(6) + 2(4) = 12 + 8 = 20

  Area = L * W = 6 * 4 = 24

After decrease:

  Perimeter = 2L + 2W = 2(6) + 2(1) = 12 + 2 = 14

  Area = L * W = 6 * 1 = 6

Percent of change in the perimeter:

20 - 14 = 6

6/20 = 0.3 or 30% decrease in perimeter

Percent of change in the area:

24 - 6 = 18

18/24 = 0.75 or 75% decrease in area

this is not the answer this is just a question. is this middle school math?

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0