How can you tell when an equation in one variable has infinitely many solutions or no solution? When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You also will end up with a true statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will also end up with a false statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will end up with a true statement, like 2 = 2 for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You will end up with a false statement, like 0 = 2 for an equation with infinitely many solutions.

How can you tell when an equation in one variable has infinitely many solutions or no solution?

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You also will end up with a true statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will also end up with a false statement for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a false statement, like 0 = 2, for an equation with no solution. You will end up with a true statement, like 2 = 2 for an equation with infinitely many solutions.

When you solve for the variable, you will end up with a true statement, like 2 = 2, for an equation with no solution. You will end up with a false statement, like 0 = 2 for an equation with infinitely many solutions.

Step-by-step explanation:

There you go homies

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =