determine the solution to the system of equations graphed below and explain your reasoning g(x)=3x+2 f(x)=|x-1|+1

(0, 1)

Step-by-step explanation:

To find the solution to these 2 functions, we just set up an equation where they're equal to each other:

3x+2 = |x-1|+1

Then, isolate the absolute value:

3x+1 = |x-1|

Now, to get rid of the absolute value sign, we can set the right-hand side to be the positive or negative version of itself.

First, let's set it to the negative version of itself:

3x+1 = -x+1

4x = 0

x = 0

Then, let's set it to the positive version of itself:

3x+1 = x-1

2x = -2

x = -2

We can now plug the x as 0 and -2 into any of the 2 equations above to find the solution for y:

3(0)+1 = 1, so the first solution will be (0, 1)

3(-2)+2 = -4.

You might be tempted to say that -4 is the y value for the 2nd solution, but notice that |x-1| will never be less than 0, so that would not work. Therefore, x = -2 isn't a solution either, which means it's an extraneous solution.

In conclusion, the solution to these equations is (0, 2).

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

ask the math teacher she or he would know lol.

step-by-step explanation: