Two cars start traveling in the same direction around a circular road that is 80 km long. The speed of one car is 92 km/h and the sped of the other is 68 km/h. How many minutes after the two cars start traveling will one car lap the other for the second time? PLEASE HELP! I WILL AWARD BRAINLIEST IF THERE ARE TWO ANSWERS!

400 minutes

Step-by-step explanation:

The speed for car 1 is 92 km/h and the speed for car two is 68 km/h. The time is unknown but we know it has to be converted into minutes so the time for both cars will be x/60. Now we multiply speed by time and get distance. The first car is 92 x/60 and the second car is 68 x/60. Cross multiply and you get 92x/60 and 68 x/60 now we can make an equation. 92x/60 - 68 x/60 = 80, x = 200. We multiply x by 2 to get the second time which is 400 minutes.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

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step-by-step explanation: