Pls help for question 4 ASfap

20%

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

median = 4

step-by-step explanation:

we are given a histogram which shows a data distribution. given that all class widths are 1, we are to find the median of this data distribution.

in any data set or distribution, median is its middle value such that the data is sorted out in an ascending order.

so here, we have 7 values and the middle value will be 4 as it separates the higher half from the lower half of the date distribution.

median = = 4

according to egenuity the correct answer is b

step-by-step explanation:

b: $9,600