Sonny and logan where driving go carts around the track. Sony took 15 minutes to drive 1 lap, it took logan 9 minutes to drive around 1 lap. If two of then start at the same time and went there same speeds, after how many minutes would the 2 of them meet at the same point?

45 minutes

Step-by-step explanation:

Let, after time minutes, they meet again at the same point.

In time minutes, let Sony completes x lap while Iogan completes y laps. Note that x and y must be the counting numbers.

As Sonny took 15 minutes to drive 1 lap, so,

While Iogan Sonny took 9 minutes to drive 1 lap, so,

[from equation (i)]

As x,y must be counting number, so

(x,y)=(3,5),(6,10),...,(3n,5n) where n is a positive integer.

So, the minimum number of laps required are

x=3 and y=5  (when they meet for the first time)

Now, from equation (i),

The time required to meet them for the first time, t=15x3=45 minutes.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

1/6

step-by-step explanation: