Sharonda uses a blend of dark chocolate and milk chocolate to make the ice cream topping at her restaurant. She needs to buy 120\,\text{kg}120kg120, start text, k, g, end text of chocolate in total for her next order, and her recipe calls for twice the amount of dark chocolate as milk chocolate. Let ddd be the number of kilograms of dark chocolate she buys and mmm be the number of kilograms of milk chocolate she buys.

Step-by-step explanation:

ATQ,

Let d be the number of kilograms of dark chocolate she buys and m be the number of kilograms of milk chocolate she buys.

She needs to buy 120 kg of chocolate in total for her next order, and her recipe calls for twice the amount of dark chocolate as milk chocolate.

So,

m = 2d (1)

m + d = 120 ...(2)

We can also solve the above equations,

Put m = 2d in equation (2)

2d + d = 120

3d=120

d = 40

Put d = 40 in equation (1)

m = 2(40)

m = 80

Hence, she will need 40 kg of dark chocolate and 80 kg of milk chocolate.

d+m=120

d=2m

Step-by-step explanation:

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation:

no of data

divide by no of mode