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(5) D       (6) D         (7) B        (8) B        (9) C

Step-by-step explanation:

5)  2 - 3n < 17      and     6n + 4 < 58

   -2           -2                        -4   -4  

       -3n  <  15                 6n      <  54

    ÷ -3    ↓ ÷ -3             ÷6          ÷6  

          n  >   -5     and       n      <   9

                    -5 <  n < 9

6) 6x + 5 > -49     and     7 - 4x ≥ -21

          -5   -5                 -7           -7

   6x       >  -54                   -4x ≥  -28

  ÷6          ÷6                 ÷ -4  ↓  ÷ -4

      x      >  -9       and           x ≤  7

                      -9 < x ≤ 7

7)  -69 ≤ 6x - 9 ≤ -45

     +9        +9   +9  

     -60 ≤ 6x     ≤  -36

    ÷6     ÷6         ÷6  

    -10  ≤   x     ≤  -6

8)  -93 ≤ 9n - 3 < -84

    +3         +3    +3

    -90 ≤ 9n      <  -81

    ÷9     ÷9        ÷9  

    -10  ≤    n     <  -9  

9)  4k - 6 ≤ -6 + 6k       or     -3k - 5 ≥ -2k + 10

  -6k               -6k             +2k       +2k        

    -2k - 6 ≤ -6                         -k - 5 ≥         10

           +6   +6                           +5            +5  

    -2k       ≤  0                         -k      ≥         15    

  ÷ -2      ↓ ÷ -2                    ÷ -1    ↓        ÷ -1  

        k     ≥    0            or            k   ≤      -15

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v