A baseball player starts the season with 77 career home runs. Ten games into the season, he has hit 2 home runs. Assume he continues at this pace. Write an
equation for the number of career home runs he has hit. How many career home
runs would you expect him to have at the end of the season (162 games)?

Using the slope intercept relation, the required equation and the number of home runs at season end would be ;

Recall :

Slope, b = 2 home runs per 10 games = 2/10 = 0.2

The expression can be represented thus:

Number of home runs at the end of the season :

x = 162

y = 0.2(162) + 77

y = 32.4 + 77

y = 109.4

y = 109

Hence, Total number of hime runs would be 109.

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If there are a total of 162 games, and every then games the player hits 2 home runs, we can divide the total amount of games by 10 then multiply the quotient by 2.

162 / 10 is approximately 16.

16 × 2 = 32

32 + 77 = 109 career home runs

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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