Taxi company charges $ 8.00 to get into the cab and $ 0.75 per mile. Taxi company B charges $ 6.00 to get into a cab and $ 1.25 per mile. How many miles would the cost be the same for both companies? help me

50 miles

Step-by-step explanation:

Let the miles traveled be x when cost for both taxi A and Taxi B is same

Lets calculate for Taxi A

charge to get in cab = $8

cost of traveling 1 mile = $ 0.75

cost of traveling for x miles = x * cost of traveling 1 mile= $ 0.75x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi A = $8 + $ 0.75x

Lets calculate for Taxi B

charge to get in cab = $3

cost of traveling 1 mile = $ 1.25

cost of traveling for x miles = x * cost of traveling 1 mile= $ 1.25x

Total cost for traveling x miles = charge to get in cab +cost of traveling for x mile

Total cost for traveling x miles in Taxi B= $3 + $ 1.25x

As we have to find distance when cost for both is same

Thus

Total cost for traveling x miles in Taxi A=Total cost for traveling x miles in Taxi B

8 +  0.75x = 3 +  1.25x

8 - 3 = 1.25x -  0.75x

5 = 0.5x

x = 5/0.5 = 50

Thus, you must travel 50 miles so that cost in both the taxi A and Taxi B is the same

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

b i think

step-by-step explanation:

not really sure